PTHH:
$$\rm a, C_2H_4+Br_2\to C_2H_4Br_2 \\ b, C_3H_6+H_2\xrightarrow{t^o,Ni} C_3H_8 \\ c, C_2H_4+H_2O\xrightarrow{H^{+},t^o} C_2H_5OH \\ d, C_3H_4+Br_2\xrightarrow{1:2} C_3H_4Br_4 \\ e, C_2H_2+2AgNO_3+2NH_3\to C_2Ag_2\downarrow+2NH_4NO_3 \\ f, 2C_3H_5(OH)_3+Cu(OH)_2\to [C_3H_5(OH)_2O]_2Cu+2H_2O \\ g, 2C_2H_5OH\xrightarrow{t^o,140^oC} C_2H_5OC_2H_5+H_2O$$

Đáp án: Giải thích các bước giải:
 a) C2H4 + Br2 -CCl4-> C2H4Br2
b)   C3H6 + 2H2 -to, Ni-> C3H8
c) C2H4 + H2O -H2SO4 loãng, t > 180- > C2H5OH
d) C3H4 + Br2 ->C3H4Br2 (1:2)
e) C2H2 + 2AgNO3 + 2NH3 -> C2Ag2  +NH4NO3 
f)2 C3H5(OH)3+ Cu(OH)2 ->[ C3H5(OH)2O ]2 Cu  +2 H2O
g) 2CH3OH -H2SO4/140°> CH3-O-CH3